**Tuesday**

*NWEA*

**Wednesday**

*NWEA*

*Classwork:* Review worksheet (Kuta)

**Tuesday**

*NWEA*

**Wednesday**

*NWEA*

*Classwork:* Review worksheet (Kuta)

**Monday**

*SNOW DAY*

**Tuesday**

*Topic:* Basic Probability

*Homework:* 11-2 G Side 1

**Wednesday**

*Topic:* Basic Probability

**Thursday**

*Topic:* Basic Probability

*Classwork:* Additional exercises

**Friday**

*SNOW DAY*

**Monday**

*SNOW DAY*

**Tuesday**

*Topic:* Basic Probability

*Homework:* 11-2 K Side 1

**Wednesday**

*Topic:* Basic Probability

**Thursday**

*Topic:* Basic Probability

*Classwork:* Additional exercises

**Friday**

*SNOW DAY*

**Monday**

*Topic:* Fundamental Counting Theorem and Permutations

**Tuesday**

*Topic:* Fundamental Counting Theorem and Permutations

*Classwork:* 11-1 G Side 1

**Wednesday**

*Topic:* Permutations and Combinations

*Classwork:* Kuta Worksheet (Permutations)

**Thursday**

*Topic:* Combinations

*Classwork:* Kuta Worksheet (Combinations)

**Friday**

*Topic:* Combinations

**Monday**

*Topic:* Fundamental Counting Theorem and Permutations

**Tuesday**

*Topic:* Fundamental Counting Theorem and Permutations

*Classwork:* 11-1 K Side 1

**Wednesday**

*Topic:* Permutations and Combinations

*Classwork:* Kuta Worksheet (Permutations)

**Thursday**

*Topic:* Combinations

*Classwork:* Kuta Worksheet (Combinations)

**Friday**

*Topic:* Combinations

Here’s an example of synthetic division using a linear divisor. Consider \((3x^3 + 2x^2 – x + 7)\div (x – 2)\). Here it is using synthetic division: \[\begin{array}{cccccc}2&|&3&2&-1&7\\&|&\downarrow&6&16&30\\&&——&——&——&——\\&&3&8&15&37\end{array}\]

The quotient is \(3x^2 + 8 + 15 + \frac{37}{x – 2}\).

Synthetic division for higher order divisors relies on the same concept, but needs a new line for each coefficient. For instance, a quadratic divisor uses two lines instead of one; a cubic divisor uses three lines; and so on.

For instance, \((x^2 + 3x – 7)(x^2 – 5x + 2) = x^4 – 2x^3 -20x^2 + 41x – 14\). To get a remainder, we’ll change the last two terms. To the left, we’ll reverse the signs of both of the coefficients of the lower terms of the divisor; as before, we’ll write all of the coefficients of the dividend: \[\begin{array}{cccccccc}-3&7&|&1&-2&-20&40&-10\\ & &|&\downarrow&-3&15&-6& \\ & &|&\downarrow&&7&-35&14\\ & & &——&——&——&——&——\\ & & &1&-5&2&-1&4\end{array}\]

In the second row, we use opposite of the coefficient from the \(x\) term (that is, -3) as a multiplier; in the third row, we use opposite of the constant (that is, 7).

This gives us a result of \(x^2 – 5x + 2 + \frac{-x + 4}{x^2 + 3x – 7}\), which is the same thing we get from long division.

Notice that, regardless, the lead coefficient (\(a\)) of the divisor must be 1. You can use synthetic division with, say, a divisor of \(4x – 5\), but you’d have to use \(x – 5/4\) instead, and then divide each coefficient of the result by 4.

For example, consider \((2x^3 + x^2 – 17x + 14)/(2x + 7)\). This is what synthetic division yields: \[\begin{array}{cccccc}-7/2&|&2&1&-17&14\\&|&\downarrow&-7&21&-14\\&&——&——&——&——\\&&2&-6&4&0\end{array}\]

The actual quotient is \(x^2 – 3x + 2\), with no remainder, which is what we get from dividing each of the resulting values by 2.

]]>All papers **must be** turned in by Friday, January 26, before I leave the building. I will be finalizing grades over the weekend. Any papers turned in after Friday will not count.

**Monday**

*Study for midterms*

*Classwork:* Study packet

**Tuesday**

*Study for midterms*

*Classwork:* Study packet

**Wednesday**

*Midterm (hours 1 and 2)*

**Thursday**

*Midterm (hour 4)*

**Friday**

*Midterm (hours 5 and 6)*